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標題:
Maths(Coordinate Treatment of Simple Locus Problems)
發問:
In the figure,Q is a point on the straight line L:x-2y-4=0 such that PQ is parallel to the x-axis.The coordinates of P is (10,5),Qis (x,5).P同Q連埋一齊~ (a)Find the coordinates of Q. (b)Find the length of PQ.
In the figure,Q is a point on the straight line L:x-2y-4=0 such that PQ is parallel to the x-axis.The coordinates of P is (10,5),Qis (x,5).P同Q連埋一齊~ (a)Find the coordinates of Q. x - 2y - 4 = 0 sub y = 5 x - 10 - 4 = 0 x = 14 Q is (14,5) (b)Find the length of PQ. Length: 14 - 10 = 4
其他解答:
Maths(Coordinate Treatment of Simple Locus Problems)
發問:
In the figure,Q is a point on the straight line L:x-2y-4=0 such that PQ is parallel to the x-axis.The coordinates of P is (10,5),Qis (x,5).P同Q連埋一齊~ (a)Find the coordinates of Q. (b)Find the length of PQ.
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最佳解答:In the figure,Q is a point on the straight line L:x-2y-4=0 such that PQ is parallel to the x-axis.The coordinates of P is (10,5),Qis (x,5).P同Q連埋一齊~ (a)Find the coordinates of Q. x - 2y - 4 = 0 sub y = 5 x - 10 - 4 = 0 x = 14 Q is (14,5) (b)Find the length of PQ. Length: 14 - 10 = 4
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