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2題簡單MATH QUESTION(中2)
1. PQ2 +QR 2 = 16 PQ+QR=? 2.GIVEN THAT THE AREA OF A SQUARE WOODEN BOARD IS 125CM2, FIND THS LENGTH OF THER DIAGONAL OF THE BOARD.( LEAVE YOUR ANSWER IN A SQUARE ROOT FORM) 更新: 第一題果到,PQ=QR
最佳解答:
Let x = PQ =QR X^2 + X^2 =16 2X^2 =16 X^2=8 X= sqrt( 8) PQ +QR = 2X = 2 sqrt (8) = 4 sqrt( 2) 2. Let y cm be the side of the square. y^2 =125 Let z cm be the length of the diagonal z^2= y^2 + y^2 z^2 =2 y^2 z^2 =2 * 125 z^2 =250 z= sqrt(250)
其他解答:
我有兩個擬問?? PQ2=(PQ)^2...??? QR 2=(QR)^2...??? IF YES, THEN: (PQ)^2+(QR)^2=16 (PQ+QR)^2-2PQ^2R=16 PQ+QR=開方(16-2PQ^2R)
2題簡單MATH QUESTION(中2)
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發問:1. PQ2 +QR 2 = 16 PQ+QR=? 2.GIVEN THAT THE AREA OF A SQUARE WOODEN BOARD IS 125CM2, FIND THS LENGTH OF THER DIAGONAL OF THE BOARD.( LEAVE YOUR ANSWER IN A SQUARE ROOT FORM) 更新: 第一題果到,PQ=QR
最佳解答:
Let x = PQ =QR X^2 + X^2 =16 2X^2 =16 X^2=8 X= sqrt( 8) PQ +QR = 2X = 2 sqrt (8) = 4 sqrt( 2) 2. Let y cm be the side of the square. y^2 =125 Let z cm be the length of the diagonal z^2= y^2 + y^2 z^2 =2 y^2 z^2 =2 * 125 z^2 =250 z= sqrt(250)
其他解答:
我有兩個擬問?? PQ2=(PQ)^2...??? QR 2=(QR)^2...??? IF YES, THEN: (PQ)^2+(QR)^2=16 (PQ+QR)^2-2PQ^2R=16 PQ+QR=開方(16-2PQ^2R)
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